Question
$\int\sin\text{x}\sqrt{1+\cos2\text{x}}\text{ dx}$

Answer

$\int\sin\text{x}\sqrt{1+\cos2\text{x}}\text{ dx}$
$=\int\sin\text{x}.\sqrt{2\cos^2\text{x}}\text{ dx}$ $[\therefore1+\cos2\text{x}=2\cos^2\text{x}]$
$=\sqrt{2}\int\sin\text{x}\cos\text{x dx}$
$=\frac{\sqrt{2}}{2}\int2\sin\text{x}\cos\text{x dx}$
$=\frac{1}{\sqrt{2}}\int\sin2\text{x dx}$
$=\frac{1}{\sqrt{2}}\Big[\frac{-\cos2\text{x}}{2}\Big]+\text{c}$
$=\frac{-1}{2\sqrt{2}}\cos2\text{x}+\text{c}$

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