MCQ
$\int\tan^{-1}\sqrt{\text{x  dx}}$ is equal to :
  • $(\text{x}+1)\tan^{-1}\sqrt{\text{x}}-\sqrt{\text{x}}+\text{c}$
  • B
    $\text{x}\tan^{-1}\sqrt{\text{x}}-\sqrt{\text{x}}+\text{c}$
  • C
    $\sqrt{\text{x}}-\text{x}\tan^{-1}\sqrt{\text{x}}+\text{c}$
  • D
    $\sqrt{\text{x}}-(\text{x}+1)\tan^{-1}\sqrt{\text{x}}+\text{c}$

Answer

Correct option: A.
$(\text{x}+1)\tan^{-1}\sqrt{\text{x}}-\sqrt{\text{x}}+\text{c}$

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