MCQ
Iodine is formed when potassium iodide reacts with a solution of
- A$ZnS{O_4}$
- ✓$CuS{O_4}$
- C${(N{H_4})_2}S{O_4}$
- D$N{a_2}S{O_4}$
✓
Answer
Correct option: B.
$CuS{O_4}$
b
(b) $CuS{O_4} + 2KI\, \to \,Cu{I_2} + {K_2}S{O_4}$
(b) $CuS{O_4} + 2KI\, \to \,Cu{I_2} + {K_2}S{O_4}$
$2Cu{I_2}\, \to \,\mathop {2CuI\,\,\,\,\,\,\, + \,\,\,\,\,{I_2}}\limits_{{\rm{Cuprous iodide}}\,\,\,\,\,\,\,\,\,\,} $
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