MCQ
Ionisation energy in group $I-A$ varies in the decreasing order as
  • $Li > Na > K > Cs$
  • B
    $Na > Li > K > Cs$
  • C
    $Li > Cs > K > Na$
  • D
    $K > Cs > Na > Li$

Answer

Correct option: A.
$Li > Na > K > Cs$
a
(a) Due to the large size of group $IA$ elements, the outermost electron is far from the nucleus and can easily be removed. their ionisation energies or ionisation potentials are relatively low.

                                   $Li$,     $Na$,     $K$,    $Rb$ ,   $Cs$

Ionisation potential $(eV) 5.4, \,\,5.1,\,\, 4.3,\,\, 4.2,\,\, 3.9$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The number of molecules in $4.25 \,g$ of ammonia are
When electron jumps from N shell to L shell, the energy is:
The compounds that will give an isomer of  $2; 2-$ dimethyl propane on catalytic hydrogenation are

$(1)$ $\begin{array}{*{20}{c}}
  {C{H_3}CH = C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(2)$ $C{H_3}CH = CHC{H_3}$

$(3)$ $\mathop {C{H_3}C}\limits^{\begin{subarray}{l} 
  \,\,\,\,\,\,\,\,{\begin{array}{*{20}{c}}
  {}&H 
\end{array}} \\ 
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,| 
\end{subarray} }  = CHC{H_2}C{H_3}$

$(4)$ $\begin{array}{*{20}{c}}
  {C{H_3}C = C - C{H_3}} \\ 
  {\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_{3\,\,}}\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$

Which of the following is a meso compound ?
Krypton ${(_{36}}Kr)$ has the electronic configuration ${(_{18}}Ar)$ $4{s^2},3{d^{10}},4{p^6}$. The ${37^{th}}$ electron will go into which one of the following sub-levels
The $IUPAC$ name of the compound $CH_2 = CH -CH (CH_3)_2$ is
In one molal solution that contains $0.5$ mole of a solute, there is
Calculate enantiomeric excees of mixture containing $6g$ of $( +) - 2$ -butanol and  $4g$ of $(-) - 2$ -butanol........$\%$
For silve ${C_P}\,\left( {J{K^{ - 1}}\,mo{l^{ - 1}}} \right) = 23 + 0.01\,T$ . If the temperature $(T)$ of $3\, moles$ of silver is raised from $300\, K$ to $1000\, K$ at $1\, atm$ pressure, the value of $\Delta H$ will be close to.....$kJ$
${H_{2(g)}}$+ ${I_{2(g)}}$ $\rightleftharpoons$ $2H{I_{(g)}}$ In this reaction when pressure increases, the reaction direction