Iqbal treated a lustrous, divalent element M with sodium hydroxid… - Vidyadip

Question

Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. Suggest how can he identify the produced gas. Write chemical equations for both the reactions.

✓

Answer

The divalent element M is a metal. It reacts with both sodium hydroxide (alkali) and dilute hydrochloric acid to evolve hydrogen gas.
$ M ( s )+2 NaOH ( aq ) \rightarrow Na _2 MO _2( aq )+ H _2(g)$
$M ( s )+2 HCl ( aq ) \rightarrow MCl _2( aq )+ H _2(g)$

The gas burns with a pop sound when a burning match stick is brought near it.

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