- A$Cu$
- ✓$Zn$
- C$Pb$
- D$Mg$
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$2HI_{(g)} \to H_{2(g)} + I_{2(g)}$
is $200 \frac {KJ}{mol}$ at $600 \,K$. Calculate the fraction of molecules of reactant having energy equal to or greater than activation energy ?
Choose the correct statement($s$) about the above process
$(A)$ $OH ^{-}$ions react with $N _2 H _4$ at the anode to form $N _2( g )$ and water, releasing 4 electrons to the anode.
$(B)$ At the cathode, $N _2 H _4$ breaks to $N _2( g )$ and nascent hydrogen released at the electrode reacts with oxygen to form water.
$(C)$ At the cathode, molecular oxygen gets converted to $OH ^{-}$.
$(D)$ Oxides of nitrogen are major by-products of the electrochemical process.
