PART - 2 CH : 3 Finding Common Ground — MATHS STD 7 — Question

Here let a = 5 × 7 × 11 × 11 and b = 5 × 7 × 7 × 11 × 2
For a number a to be a multiple of number b, all prime factors of b must be present in a with at least the same power.
Number a does not have the prime factor 2.
Number a has 71, while number b has 7.
Hence, a is not a multiple of b.