Question
Is it possible to design a rectangular mango grove whose length is twice its breadth and the area is 800m$^2$? If so, find its length and breadth.
✓
Answer
Let the breadth of the rectangular mango grove be x meter.
Given that length is twice that of breadth,
lengrh = 2 × xm
Given that area of the grove is 800m$^2$.
But we know that
Area of a rectangle = length × breadth
$\Rightarrow 800m^2 = 2xm \times xm$
$\Rightarrow 2x^2 = 800$
$\Rightarrow x^2 = 400$
$\Rightarrow\text{x}=\sqrt{400}$
$\Rightarrow\text{x}=\sqrt{(20)^2}$
$\Rightarrow\text{x}\pm20$
Since, x cannot be a negative value
So, x = 20m
Breadth of the manogo grove = 20m and length of the mango grove
= 2xm = 2 × 20m = 40m
Yes. It is possible to dising a rectangular mango grove whose length is twice its breadth and the area is 800m$^2$.
Given that length is twice that of breadth,
lengrh = 2 × xm
Given that area of the grove is 800m$^2$.
But we know that
Area of a rectangle = length × breadth
$\Rightarrow 800m^2 = 2xm \times xm$
$\Rightarrow 2x^2 = 800$
$\Rightarrow x^2 = 400$
$\Rightarrow\text{x}=\sqrt{400}$
$\Rightarrow\text{x}=\sqrt{(20)^2}$
$\Rightarrow\text{x}\pm20$
Since, x cannot be a negative value
So, x = 20m
Breadth of the manogo grove = 20m and length of the mango grove
= 2xm = 2 × 20m = 40m
Yes. It is possible to dising a rectangular mango grove whose length is twice its breadth and the area is 800m$^2$.
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