MCQ
is prepared best by the reaction
- A$(CH_3)_3 C-Br + CH_3OK \to$
- B${(C{H_3})_3}C - OH\xrightarrow[{{{170}\,^o}C}]{{{H_2}SO}}$
- ✓$(CH_3)_3 COK + CH_3-Br \to$
- D${(C{H_3})_2}C = C{H_2}\xrightarrow{{Conc.\,\,{H_2}S{O_4}}}$
✓
Answer
Correct option: C.
$(CH_3)_3 COK + CH_3-Br \to$
c
$(CH_3)_3COK + CH_3-Br \to (CH_3)_3C-O-CH_3$
$(CH_3)_3COK + CH_3-Br \to (CH_3)_3C-O-CH_3$
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