MCQ
is $ \text{f(x)} = \displaystyle \frac {\text{x}^2+6\text{x}}{\sin \text{x}}$ then $\lim_\limits{\text{x} \rightarrow 0} \text{f(x)=}$
- A$2$
- B$4$
- ✓$6$
- D$8$
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