Question
Is the given statement correct or not correct?
If two coins are tossed simultaneously there are three possible outcomes- two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is $\frac{1}{3}$.

Answer

All possible outcomes = (H, H), (H, T), (T, H), (T, T)
Probability of an event = $\frac{\text { Favourabe outcomes }}{\text { Total outcomes }}$
Probability (2 heads) = $\frac{1}{4}$
Probability (2 tails) = $\frac{1}{4}$
It is not correct.
If we want to get the probability of them we should categorize the outcomes like this but they are not equally likely because one of each can result in two ways from a head-on first coin and tail on second or from the tail on first and head on second.

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