Question
Isomers have essentially identical
✓
Answer
d
(d) Five isomers of ${C_4}{H_8}$
(d) Five isomers of ${C_4}{H_8}$
1. $\mathop {C{H_3} - \mathop {\mathop {C{\mkern 1mu} {\mkern 1mu} = {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} }\limits^{|{\kern 1pt} {\kern 1pt} {\kern 1pt} \,\,\,\,\,{\kern 1pt} {\kern 1pt} {\kern 1pt} } }\limits^{C{H_{3\,\,}}\,\,\,} C{H_2}}\limits_{{\text{Isobutene}}} $
2. $\mathop {C{H_3}C{H_2} - CH = C{H_2}}\limits_{{\text{1 - butene}}} $
3. $\mathop {\begin{array}{*{20}{c}}
{{H_2}C{\mkern 1mu} - C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} |} \\
{{H_2}C - C{H_2}}
\end{array}}\limits_{Cyclobu\tan e} {\mkern 1mu} $
4. $\underset{Trans-2-butene}{\mathop{\begin{matrix}
^{C{{H}_{3}}} \\
_{H} \\
\end{matrix}\begin{matrix}
\text{ }\!\!\backslash\!\!\text{ } \\
/ \\
\end{matrix}C=C\begin{matrix}
/ \\
\text{ }\!\!\backslash\!\!\text{ } \\
\end{matrix}_{C{{H}_{3}}}^{H}}}\,$
5. $\underset{cis-2-butene}{\mathop{\begin{matrix}
^{C{{H}_{3}}} \\
_{H} \\
\end{matrix}\begin{matrix}
\text{ }\!\!\backslash\!\!\text{ } \\
/ \\
\end{matrix}C=C\begin{matrix}
/ \\
\text{ }\!\!\backslash\!\!\text{ } \\
\end{matrix}_{C{{H}_{3}}}^{C{{H}_{3}}}}}\,$
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