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MODEL PAPER 4 — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistryMODEL PAPER 41 Mark
MCQ
Isomers of the compound $\ce{C_4H_9Br}$ are$:$
  • A
    $1-$Bromo$-2-$methylbutane and$ 2-$Bromo$-2-$ methylbutane
  • B
    $1-$ Bromobutane and $2 -$ Bromobutane
  • ✓
    $1 -$ Bromobutane, $2 -$ Bromobutane, $1 -$ bromo$-2-$methylpropane, and $2 -$ bromo$-2 -$ methylpropane
  • D
    $1-$Bromo$-2-$methylpropane and $2 -$ Bromo$-2-$methylpropane
✓

Answer

Correct option: C.
$1 -$ Bromobutane, $2 -$ Bromobutane, $1 -$ bromo$-2-$methylpropane, and $2 -$ bromo$-2 -$ methylpropane
Isomers are compounds having the same molecular formula but different structures. In the given straight$-$chain $4-C$ compounds, $Br$ is placed at different positions but the molecular formula is same.
Image
In the given branched $4-C$ compounds, there is a branching of $-CH_3$ at carbon $2$ but $Br$ is placed at positions $1$ and $2$ respectively.
Image
So, all of these are isomers since they have the same molecular formula but different structures.

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