Question
It is given that the functions $f(x) = 3x^2 - 1$ and $g(x) = 3 + x$ are equal.

Answer

$\therefore f(x) = g(x)$
$\Rightarrow 3x^2 - 1 = 3 + x$
$\Rightarrow 3x^2 - x - 4 = 0$
$\Rightarrow (x + 1)(3x - 4) = 0$
$\Rightarrow x + 1 = 0$ or $3x - 4 = 0$
$\Rightarrow x = -1$ or $\text{x}=\frac{4}{3}$

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