MCQ
$IUPAC$ name of $C{H_3} - CH = CH - C \equiv CH$ is
- APent $-2-$ en $-4-$ yne
- ✓Pent $-3-$ en $-1-$ yne
- CPent $-3-$ yne $-1-$ en
- DPent $-2-$ yne $-1- $ en
✓
Answer
Correct option: B.
Pent $-3-$ en $-1-$ yne
b
$C{H_3} - CH = CH - C \equiv CH$
$C{H_3} - CH = CH - C \equiv CH$
In this case $1^{\text {st }}$ prionity is given to triple bond (Terminals) over double bond and there are $5$ No. af carbons chains. therefore the Name of Compound Should be $3$-pent-$3$-ene-$1$-yne. Hence the Correct option is $c$.
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