MCQ
$IUPAC$ name of $C{H_3} - CH = CH - C \equiv CH$ is
  • A
    Pent $-2-$ en $-4-$ yne
  • Pent $-3-$ en $-1-$ yne
  • C
    Pent $-3-$ yne $-1-$ en
  • D
    Pent $-2-$ yne $-1- $ en

Answer

Correct option: B.
Pent $-3-$ en $-1-$ yne
b
$C{H_3} - CH = CH - C \equiv CH$

In this case $1^{\text {st }}$ prionity is given to triple bond (Terminals) over double bond and there are $5$ No. af carbons chains. therefore the Name of Compound Should be $3$-pent-$3$-ene-$1$-yne. Hence the Correct option is $c$.

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