MCQ
$IUPAC$ name of $[Pt (NH_3)_2 Cl(NO_2)]$ is
- ✓Platinum diaminechloronitrite
- BChloronitrito $-N-$ ammineplatinum $(II)$
- CDiamminechloridonitrito $-N-$ platinum $(II)$
- DDiamminechloronitrito $-N-$ platinate $(II)$
$Cl$ has a $-1$ charge, making the second complex the anion and so platinum ends with -ate.
Therefore, the complex with $NH _3$ comes first, followed by the one with $Cl$.
Option $(A)$ is correct. The $I.U.P.A.C$ name for $\left[ Pt \left( NH _3\right)_4\right]\left[ PtCl _4\right]$
is $tetraammineplatinum(II)$ $tetrachloridoplatinate(II)$
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