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જો $\left|\begin{array}{ccc}x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+\lambda^2\end{array}\right|=\frac{9}{8}(103 x+81)$, હોય,તો $\lambda$, $\frac{\lambda}{3}$ એ $.........$ સમીકરણના બીજ છે.