MCQ
જો $A + B = \frac{\pi }{4},$ તો $(1 + \tan A)(1 + \tan B) = $
- A$1$
- ✓$2$
- C$\infty $
- D$-2$
$\Rightarrow \,\tan \,(A + B) = \tan \,\frac{\pi }{4}$
$ \Rightarrow \,\,\frac{{\tan A + \tan B}}{{1 - \tan A\,\tan B}} = 1$
$ \Rightarrow \,\,\tan A + \tan B + \tan A\,\tan B = 1$
$ \Rightarrow \,\,(1 + \tan A)\,(1 + \tan B) = 2$.
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