MCQ
જો $sin\theta_1 + sin\theta_2 + sin\theta_3 = 3,$ થાય તો $cos\theta_1 + cos\theta_2 + cos\theta_3=$
- A$3$
- B$2$
- C$1$
- D$0$
$\therefore \quad \sin \theta_{1}=\sin \theta_{2}=\sin \theta_{3}=1$
$\Rightarrow \quad \theta_{1}=\theta_{2}=\theta_{3}=\frac{\pi}{2}$
$ \therefore \quad \cos \theta_{1}=\cos \theta_{2}=\cos \theta_{3}=0 $
$ \therefore \quad \cos \theta_{1} =\cos \theta_{2}=\cos \theta_{3}=0 $
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