MCQ
જો $x = {e^{y + {e^{y + ....t{\rm{o}}\,\,\infty }}}}$, $x > 0,$ તો ${{dy} \over {dx}} = . . . . .$
- A${{1 + x} \over x}$
- B${1 \over x}$
- ✓${{1 - x} \over x}$
- D${x \over {1 + x}}$
Taking log to the both sides, $\log x = (y + x)$
Differentiate both sides w.r.t. $x,$ $\frac{1}{x} = \frac{{dy}}{{dx}} + 1$
$ \Rightarrow \frac{{dy}}{{dx}} = \frac{{1 - x}}{x}$.
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