MCQ
જો ${x^y}.{y^x} = 1$, તો ${{dy} \over {dx}} =$
- A${{y\,(y + x\log y)} \over {x(y\log x + x)}}$
- B${{y\,(x + y\log x)} \over {x(y + x\log y)}}$
- ✓$ - {{y(y + x\log y)} \over {x(x + y\log x)}}$
- Dએકપણ નહીં
$\therefore$ ${{dy} \over {dx}} = - \frac{{{\partial f} \over {\partial x}} }{{{\partial f} \over {\partial y}} }$
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