MCQ
જો $y = {e^{\sqrt x }}$, તો ${{dy} \over {dx}} =. . .$
- ✓${{{e^{\sqrt x }}} \over {2\sqrt x }}$
- B${{\sqrt x } \over {{e^{\sqrt x }}}}$
- C${x \over {{e^{\sqrt x }}}}$
- D${{2\sqrt x } \over {{e^{\sqrt x }}}}$
==> $\frac{{dy}}{{dx}} = {e^{\sqrt x }}.\frac{d}{{dx}}\sqrt x $
==> $\frac{{dy}}{{dx}} = \frac{{{e^{\sqrt x }}}}{{2\sqrt x }}$.
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