MCQ
જ્યારે $C{H_2} = CH - COOH$ is reduced with $LiAl{H_4}$, the compound obtained will be
- A$C{H_3} - C{H_2} - COOH$
- ✓$C{H_2} = CH - C{H_2}OH$
- C$C{H_3} - C{H_2} - C{H_2}OH$
- D$C{H_3} - C{H_2} - CHO$
✓
Answer
Correct option: B.
$C{H_2} = CH - C{H_2}OH$
b
(b) $C{H_2} = CH - COOH\xrightarrow{{LiAl{H_4}}}$ $C{H_2} = CH - C{H_2}OH + {H_2}O$
(b) $C{H_2} = CH - COOH\xrightarrow{{LiAl{H_4}}}$ $C{H_2} = CH - C{H_2}OH + {H_2}O$
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