MCQ
જ્યારે $C{H_2} = CH - COOH$ is reduced with $LiAl{H_4}$, the compound obtained will be
- A$C{H_3} - C{H_2} - COOH$
- ✓$C{H_2} = CH - C{H_2}OH$
- C$C{H_3} - C{H_2} - C{H_2}OH$
- D$C{H_3} - C{H_2} - CHO$
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$(A)$ The hypochlorite ion is the strongest conjugate base.
$(B)$ The molecular shape of only chlorate ion is influenced by the lone pair of electrons of $Cl$.
$(C)$ The hypochlorite and chlorate ions disproportionate to give rise to identical set of ions.
$(D)$ The hypochlorite ion oxidizes the sulfite ion.
$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
| S.No | Time/s | Total Pressure/(atm) |
| $1.$ | $0$ | $0.1$ |
| $2.$ | $115$ | $0.28$ |
The rate constant of the reaction is_____$\times 10^{-2} \mathrm{~s}^{-1}$ (nearest integer)