MCQ
$KI$ is oxidised into $I_2$ by using the reagent
- A$KMnO_4$ (neutral or slightly alkaline solution)
- BOzone (alkaline solution)
- ✓$CuSO_4$ solution
- DAll of these
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${N_2}(g)\, + \,{O_2}(g)\,\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}\,2NO(g)$
$C_0=Ce^{-2.1 \times 10^{-3}t}$ for the forward reaction and $C'_0=C'e^{-4.2 \times 10^{-4}t}$ for the backward reaction, hence $K_c$ for the above equilibrium is :-
In an equilibrium mixture, the partial pressures are
$P_{S O_{3}}=43\,\mathrm{kPa} ; \quad P_{O_{2}}=530 \,\mathrm{~Pa}$ and
$\mathrm{P}_{\mathrm{SO}_{2}}=45\, \mathrm{kPa}$ The equilibrium constant $\mathrm{K}_{\mathrm{p}}=......\times 10^{-2} .$ (Nearest integer)
