Second case : \(\eta_{\text {net }}=\eta_{1}+\eta_{2}-\eta_{1} \eta_{2}\)

\(\eta_{1}=1-\frac{200}{300}=\frac{1}{3}\)

\(\eta_{2}=1-\frac{100}{200}=\frac{1}{2}\)

\(\eta_{\text {net }}=\frac{1}{3}+\frac{1}{2}-\frac{1}{6}=\frac{2}{3}\)

\(\eta\) (first case) \(=\eta\) (second case)