MCQ
$K_{sp}$ of $M(OH)_2$ is $3.2\times10^{-11}$. The $pH$ of saturated solution in water is
- A$3.40$
- B$10.30$
- ✓$10.60$
- D$3.70$
✓
Answer
Correct option: C.
$10.60$
c
${K_{sp}} = 4{S^3} = 3.2 \times {16^{ - 11}}$ $\therefore \,S = 2 \times {10^{ - 4}}\,M$
${K_{sp}} = 4{S^3} = 3.2 \times {16^{ - 11}}$ $\therefore \,S = 2 \times {10^{ - 4}}\,M$
$[O\bar H] = 2S = 2 \times 2 \times {10^{ - 4}}\,M$
$\therefore \,pH = 14 - pOH$
$ = 14 + \log \,4 \times {10^{ - 4}} = 10.60$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Among the following, reaction($s$) which gives(give) tert-butyl benzene as the major product is(are)
→The alkene formed as a major product in the below elimination reaction is
What will be the volume of $O_2$ gas at $STP$ which is obtained by thermal decomposition of $30.62\,g$ $KClO_3$, with $80\%$ purity ........... $\mathrm{L}$
→Which of the following compounds is insoluble even in hot concentrated $\mathrm{H}_2 \mathrm{SO}_4\ ?$
→Assertion : $2-$ Bromobutane on reaction with sodium ethoxide in ethanol gives $1-$ butene as a major product.
→Reason : $1-$ Butene is more stable than $2-$ butene According to Saytzeff's rule, $2-$ butene should be the product which is more branched or substituted compound and hence, more stable than butene $-1$
The number of structural isomers possible for the molecular formula $C_4H_8F_2$ are
→$20\,mL$ of $0.1\,M\,NaOH$ is added to $50\,mL$ of $0.1\,M$ acetic acid solution. The $pH$ of the resulting solution is $.......\times 10^{-2}$ (Nearest integer)
→$\text { Given : pKa }\left( CH _3 COOH \right)=4.76$
$\log 2=0.30$
$\log 3=0.48$
The correct representation for solubility product of $Sn{S_2}$ is
→Which of the following represents ketones?
Accurate determination of atomic masses is done with the instrument called as