- A$N{H_4}Cl$
- B${(N{H_4})_2}S{O_4}$
- C$N{H_4}Cl + NaN{O_3}$
- ✓$N{H_4}N{O_3}$
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Statement $I$: The boiling point of hydrides of Group $16$ elements follow the order
$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{~S}$.
Statement $II$: On the basis of molecular mass, $\mathrm{H}_2 \mathrm{O}$ is expected to have lower boiling point than the othe members of the group but due to the presence of extensive $\mathrm{H}$-bonding in $\mathrm{H}_2 \mathrm{O}$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
$A = - 0.250\,V$ $B = - 0.136\,V$ $C = - 0.126\,V$ $D = - 0.402\,V$
The element that displaces $A$ from its compounds is