- A${H_2}(g)\, + \,{I_2}(g)\,\, \rightleftharpoons \,\,2HI(g)$
- ✓$Fe(s)\,\, + \,S(s)\, \rightleftharpoons \,FeS(s)$
- C${N_2}(g)\, + \,3{H_2}(g)\,\, \rightleftharpoons \,\,2NH_3(g)$
- D${N_2}(g)\, + \,{O_2}(g)\,\, \rightleftharpoons \,\,2NO(g)$
Le- Chatelier principle is applicable only to gases. But it is not necessary that in a certain chemical reaction, all the reactants species must be in gaseous phase. $Fe ( s )+ S ( s ) \rightleftharpoons FeS ( s )$ is in solid equilibrium phase.
Hence, Le- Chatelier principle is not applicable.
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$(A) \,2p_y +2p_y \to \pi-$ Bond formation
$(B) \,2p_x + 2p_x \to \sigma-$ Bond formation
$(C)\, 3d_{xy} + 3dp_{xy} \to \pi$ -Bond formation
$(D)\, 2s + 2p_y \to \pi-$ Bond formation
$(E)\, 3d_{xy} + 3d_{xy} \to \delta -$ Bond formation
$(F)\, 2p_s + 2p_s \to \sigma-$ Bond formation

$I. n = 4,l = 2,m_l = -2, m_s = -1/ 2$
$II. n = 3,l = 2, m_l = 1,m_s = +1/ 2$
$III. n = 4,l = 1, m_l = 0, m_s = +1/ 2$
$IV. n = 3,l = 1, m_l = 1; m_s = -1/ 2$
The correct order of their increasing energies will be