MCQ
${\left[ {\begin{array}{*{20}{c}}{ - 6}&5\\{ - 7}&6\end{array}} \right]^{ - 1}}$=
  • $\left[ {\begin{array}{*{20}{c}}{ - 6}&5\\{ - 7}&6\end{array}} \right]$
  • B
    $\left[ {\begin{array}{*{20}{c}}6&{ - 5}\\{ - 7}&6\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}6&5\\7&6\end{array}} \right]$
  • D
    $\left[ {\begin{array}{*{20}{c}}6&{ - 5}\\7&{ - 6}\end{array}} \right]$

Answer

Correct option: A.
$\left[ {\begin{array}{*{20}{c}}{ - 6}&5\\{ - 7}&6\end{array}} \right]$
a
(a) Since $\left[ {\begin{array}{*{20}{c}}{ - 6}&5\\{ - 7}&6\end{array}} \right]\,\,\left[ {\begin{array}{*{20}{c}}{ - 6}&5\\{ - 7}&6\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&0\\0&1\end{array}} \right]$.

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