MCQ
${\left( {\frac{{1 + i}}{{1 - i}}} \right)^2} + {\left( {\frac{{1 - i}}{{1 + i}}} \right)^2}$is equal to
  • A
    $2i$
  • B
    $ - 2i$
  • $ - 2$
  • D
    $2$

Answer

Correct option: C.
$ - 2$
c
(c) ${\left( {\frac{{1 + i}}{{1 - i}}} \right)^2} + {\left( {\frac{{1 - i}}{{1 + i}}} \right)^2} = \frac{{2i}}{{ - 2i}} + \left( {\frac{{ - 2i}}{{2i}}} \right) = - 2$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free