MCQ
$\left(\frac{1}{x}+\frac{1}{y}\right)\left(\frac{1}{x}-\frac{1}{y}\right)=?$
  • $\left(\frac{1}{x^2}-\frac{1}{y^2}\right)$
  • B
    $\left(\frac{1}{x^2}+\frac{1}{y^2}\right)$
  • C
    $\left(\frac{1}{x^2}+\frac{1}{y^2}-\frac{1}{x y}\right)$
  • D
    $\left(\frac{1}{x^2}-\frac{1}{y^2}+\frac{1}{x y}\right)$

Answer

Correct option: A.
$\left(\frac{1}{x^2}-\frac{1}{y^2}\right)$
A

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