MCQ
$\left(\frac{2}{3} \sin 0^{\circ}-\frac{4}{5} \cos 0^{\circ}\right)$ is equal to:
  • A
    $\frac{2}{3}$
  • $\frac{-4}{5}$
  • C
    $0$
  • D
    $\frac{-2}{15}$

Answer

Correct option: B.
$\frac{-4}{5}$
(b)
$\sin 0^{\circ}=0$ and $\cos 0^{\circ}=1=-\frac{4}{5}$

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