MCQ
${\left( {\frac{{\sqrt 3 + i}}{2}} \right)^6} + {\left( {\frac{{i - \sqrt 3 }}{2}} \right)^6}$is equal to
- ✓$- 2$
- B$0$
- C$2$
- D$1$
$\left( {\because \,\,\,\omega = \frac{{ - 1 + \sqrt 3 i}}{2},{\omega ^2} = \frac{{ - 1 - \sqrt 3 i}}{2}} \right)$
$ = - (1 + 1) = - 2$.
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Statement $-I$ : ${A^{ - 1}} = \frac{1}{7}\left( {5I - A} \right).$
Statement $II$ : the polynomial $A^3 - 2A^2 - 3A + I$ can be reduced to $5\, (A - 4I)$.