MCQ
$\left(2^{2} \times 2\right)^{2}=$
- A$2^{3}$
- B$2^{4}$
- C$2^{5}$
- ✓$2^{6}$
✓
Answer
Correct option: D.
$2^{6}$
$\left(2^{2} \times 2\right)^{2}=\left(2^{2+1}\right)^{2}=\left(2^{3}\right)^{2}=2^{3 \times 2}=2^{6}$
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