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Matrics — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsMatrics2 Marks
MCQ
$\left[\begin{array}{cc}1 & -1 \\ 2 & 3\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$ $A, R_2 \rightarrow R_2-2 R_1$ gives
  • A
    $\left[\begin{array}{cc}1 & -1 \\ 0 & 1\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ -2 & 1\end{array}\right] A$
  • ✓
    $\left[\begin{array}{cc}1 & -1 \\ 0 & 5\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ -2 & 1\end{array}\right] A$
  • C
    $\left[\begin{array}{cc}1 & -1 \\ 0 & 5\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 2 & 1\end{array}\right] A$
  • D
    $\left[\begin{array}{cc}1 & -1 \\ 0 & 5\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ -2 & 0\end{array}\right] A$
✓

Answer

Correct option: B.
$\left[\begin{array}{cc}1 & -1 \\ 0 & 5\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ -2 & 1\end{array}\right] A$
(B) $\left[\begin{array}{cc}1 & -1 \\ 2 & 3\end{array}\right]=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right] A$
Applying $R _2 \rightarrow R _2-2 R _1$,
$\left[\begin{array}{cc}1 & -1 \\ 2-2(1) & 3-2(-1)\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ 0-2(1) & 1-2(0)\end{array}\right] A$
$\left[\begin{array}{cc}1 & -1 \\ 0 & 5\end{array}\right]=\left[\begin{array}{cc}1 & 0 \\ -2 & 1\end{array}\right] A$

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