MCQ
$\left\{C_1+2 C_2+3 C_3+\ldots+n C_n\right\}=?$
  • A
    $( n -1) \cdot 2^{ n }$
  • B
    $n \cdot 2^n$
  • C
    $( n +1) \cdot 2^n$
  • $n \cdot 2^{n-1}$

Answer

Correct option: D.
$n \cdot 2^{n-1}$
$C _1+2 C _2+3 C _3+\ldots+n C _{ n }$
$= n +2 \cdot \frac{ n ( n -1)}{2}+3 \cdot \frac{n(n-1)(n-2)}{3!}+\ldots+n$
$= n \cdot\left[1+( n -1) \frac{( n -1)( n -2)}{2!}+\ldots+1\right]$
$= n \cdot\left[{ }^{( n -1)} C _0+{ }^{( n -1)} C _1+{ }^{( n -1)} C _2+\ldots+{ }^{( n -1)} C _{ n -1}\right]$
$= n \cdot(1+1)^{ n -1}= n \cdot 2 ^{ n -1}$

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