[ (-1 2 )^2 ^ -2 ]^ -1 =? - Vidyadip

MCQ

$\left[\left\{\left(-\frac{1}{2}\right)^2\right\}^{-2}\right]^{-1}=?$

✓
$\frac{1}{16}$
B
16
C
$-\frac{1}{16}$
D
-16

✓

Answer

Correct option: A.

$\frac{1}{16}$

A

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