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STD 12 - 3 and 4 . determinant and metrices — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 3 and 4 . determinant and metrices1 Mark
MCQ
$\left| {\begin{array}{*{20}{c}}0&a&{ - b}\\{ - a}&0&c\\b&{ - c}&0\end{array}} \right| = $
  • A
    $ - 2abc$
  • B
    $abc$
  • ✓
    $0$
  • D
    ${a^2} + {b^2} + {c^2}$
✓

Answer

Correct option: C.
$0$
c
(c)$\left| {\,\begin{array}{*{20}{c}}0&a&{ - b}\\{ - a}&0&c\\b&{ - c}&0\end{array}\,} \right| = 0$ (Since value of determinant of skew-symmetric matrix of odd orders is $0$).

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