MCQ
$\left| {\,\begin{array}{*{20}{c}}{11}&{12}&{13}\\{12}&{13}&{14}\\{13}&{14}&{15}\end{array}\,} \right| = $
  • A
    $1$
  • $0$
  • C
    $-1$
  • D
    $67$

Answer

Correct option: B.
$0$
b
(b)Apply ${C_3} \to {C_3} - {C_2}$ and ${C_2} \to {C_2} - {C_1}$.

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