| , * 20 c 1/a &1& bc 1/b &1& ca 1/c &1& ab , | = - Vidyadip

MCQ

$\left| {\,\begin{array}{*{20}{c}}{1/a}&1&{bc}\\{1/b}&1&{ca}\\{1/c}&1&{ab}\end{array}\,} \right| = $

✓
$0$
B
$abc$
C
$1/abc$
D
None of these

✓

Answer

Correct option: A.

$0$

a
(a) $\Delta = \frac{1}{a}[ab - ca] + 1\left[ {ca.\frac{1}{c} - \frac{1}{b}.ab} \right] + bc\left[ {\frac{1}{b} - \frac{1}{c}} \right]$

==>$\Delta = (b - c) + 1(a - a) + (c - b)$

==> $\Delta = 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 3 and 4 . determinant and metrices→STD 12 - 3 and 4 . determinant and metrices — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

$\int(1+2\text{x}+3\text{x}^2+4\text{x}^3+ ... )\text{dx }(\mid\text{x}\mid<1)$

If ${A^2} - A + I = 0$, then ${A^{ - 1}}$ =

The area under the curve $y= 2x^3+ 4x^2$ between $x = 2, x = 4$ is:

Interval in which function $y = |x^2 -|x| -2|$ is non monotonic, can be-

If the function f(x) defined by $\text{f(x)}=\begin{cases}\frac{\log(1+3\text{x})-\log(1-2\text{x})}{\text{x}},&\text{x}\neq0\\\text{k},&\text{x}=0\end{cases}$ is continuous at x = 0, then k =

$\frac{\text{d}}{\text{dx}}\bigg[\log\bigg\{\text{e}^\text{x}\Big(\frac{\text{x}-2}{\text{x}+2}\Big)^\frac{3}{4}\bigg\}\bigg]$ equals:

$\int_{0}^{1}\frac{\text{x}}{1+\text{x}}\text{dx}=$

If $f(x) = 4x^8,$ then:

The scalar projection of the vector $3 \hat{ i }-\hat{ j }-2 \hat{ k }$ on the vector $\hat{i}+2 \hat{j}-3 \hat{k}$ is

The number of integral solutions (x, y) of the equations $\text{x}{\sqrt{\text{y}}}+\text{y}\sqrt{\text{x}}=20$ and $\text{x}{\sqrt{\text{x}}}+\text{y}\sqrt{\text{y}}=65$ is: