MCQ
$\left| {\,\begin{array}{*{20}{c}}1&{1 + ac}&{1 + bc}\\1&{1 + ad}&{1 + bd}\\1&{1 + ae}&{1 + be}\end{array}\,} \right| = $
- A$1$
- ✓$0$
- C$3$
- D$a + b + c$
we get $\left| {\,\begin{array}{*{20}{c}}1&{ac}&{bc}\\1&{ad}&{bd}\\1&{ae}&{be}\end{array}\,} \right| = ab\left| {\,\begin{array}{*{20}{c}}1&c&c\\1&d&d\\1&e&e\end{array}\,} \right| = 0$,.
$\{ \because {C_2} \equiv {C_3}\} $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$7 \times 8,10 \times 10,13 \times 12,16 \times 14, \ldots .$ is ....... .