MCQ
$\left| {\,\begin{array}{*{20}{c}}1&a&b\\{ - a}&1&c\\{ - b}&{ - c}&1\end{array}\,} \right| = $
  • $1 + {a^2} + {b^2} + {c^2}$
  • B
    $1 - {a^2} + {b^2} + {c^2}$
  • C
    $1 + {a^2} + {b^2} - {c^2}$
  • D
    $1 + {a^2} - {b^2} + {c^2}$

Answer

Correct option: A.
$1 + {a^2} + {b^2} + {c^2}$
a
(a) $\left| {\,\begin{array}{*{20}{c}}1&a&b\\{ - a}&1&c\\{ - b}&{ - c}&1\end{array}\,} \right| = 1\,(1 + {c^2}) - a( - a + bc) + b(ac + b)$

= $1 + {a^2} + {b^2} + {c^2}$.

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