| , * 20 c a + b & b + c & c + a b + c & c + a & a + b c + a & a … - Vidyadip

MCQ

$\left| {\,\begin{array}{*{20}{c}}{a + b}&{b + c}&{c + a}\\{b + c}&{c + a}&{a + b}\\{c + a}&{a + b}&{b + c}\end{array}\,} \right| = K\,\,\left| {\,\begin{array}{*{20}{c}}a&b&c\\b&c&a\\c&a&b\end{array}\,} \right|\,,$ then $K = $

A
$1$
✓
$2$
C
$3$
D
$4$

✓

Answer

Correct option: B.

$2$

b
(b) The determinant can be written sum of $2 \times 2 \times 2 = 8$ determinants of which $ 6 $ are reduces to zero because of their two rows are identical. Hence proceed.

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