Question
$\left(x-\frac{a}{b}\right)^2=\frac{a^2}{b^2}$

Answer

$\left(x-\frac{a}{b}\right)^2=\frac{a^2}{b^2} $
$ \Rightarrow x^2+\frac{a^2}{b^2}-\frac{2 a x}{b}=\frac{a^2}{b^2} $
$ \Rightarrow x^2-\frac{2 a x}{b}=0 $
$ \Rightarrow x\left(x-\frac{2 a}{b}\right)=0 $
$ \Rightarrow x =0 \text { or } x -\frac{2 a}{b}=0 $
$ \Rightarrow x =0 \text { or } x =\frac{2 a}{b} $

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