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Answer
$A=\{1,2\} \text { and } B=\{3,4\}$
$\therefore A \times B=\{(1,3),(1,4),(2,3),(2,4)\}$
$=n(A \times B)=4$
We know that if $C$ is a set with $n(C)=m$, then $n[P(C)]=2^m$.
Therefore, the set $\mathrm{A} \times \mathrm{B}$ has $2^4=16$ subsets. These are
$\phi,\{(1,3)\},\{(1,4)\},\{(2,3)\},\{(2,4)\},\{(1,3),(1,4)\},\{(1,3),(2,3)\},\{(1,3),(2,4)\},\{(1,4),(2,3)\},\{(1,4),(2,4)\},\{(2,3),(2,4)\},\{(1,3),(1,4),(2,3)\},\{(1,3),(1,4),(2,4)\},\{(1,3),(2,3),(2,4)\},\{(1,4),(2,3),(2,4)\},\{(1,3),(1,4),(2,3),(2,4)\}$
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