Question
Let A and B be two stes such that: $\text{n(P)} = 20,$ $\text{n(A}\cup\text{B)=42 and n(A}\cap\text{B})=4.$ Find:
$\text{n(B)}.$
$\text{n(B)}.$
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| $\text{Column} \ C_1$ | $\text{Column}\ C_2$ | ||
| $(a)$ | The coordinates of the points $P$ and $Q$ on the line $x + 5y = 13$ which are at a distance of $2$ units from the line $12x - 5y + 26 = 0$ are | (i) | $(3, 1), (-7, 11) $ |
| $(b)$ | The coordinates of the point on the line $x + y = 4,$ which are at a unit distance from the line $4x + 3y - 10 = 0$ are | (ii) | $-\frac{1}{3},\frac{11}{3},\frac{4}{3},\frac{7}{3}$ |
| $(c)$ | The coordinates of the point on the line joining $A (-2, 5)$ and $B (3, 1)$ such that$ AP = PQ = QB$ are | (iii) | $1,\frac{12}{5},-3,\frac{16}{5}$ |