MCQ
Let $A=\{2,3,6,7\}$ and $B=\{4,5,6,8\}$. Let $R$ be a relation defined on A $\times$ B by $\left(a_1, b_1\right) R\left(a_2, b_2\right)$ is and only if $a_1+a_2=b_1+b_2$. Then the number of elements in $\mathrm{R}$ is ...........
  • A
    $34$
  • $25$
  • C
    $31$
  • D
    $20$

Answer

Correct option: B.
$25$
b
$ A=\{2,3,6,7\} $

$ B=\{2,5,6,8\} $

$ \left(a_1, b_1\right) R\left(a_2, b_2\right) $

$ a_1+a_2=b_1+b_2$

$1$. $(2,4) \mathrm{R}(6,4) \quad$ 2. $(2,4) \mathrm{R}(7,5)$

$3$. $(2,5) \mathrm{R}(7,4) \quad$ 4. $(3,4) \mathrm{R}(6,5)$

$5$. $(3,5) \mathrm{R}(6,4) \quad$ 6. $(3,5) \mathrm{R}(7,5)$

$7$. $(3,6) \mathrm{R}(7,4) \quad$ 8. $(3,4) \mathrm{R}(7,6)$ $\times 2$

$9$. $(6,5) \mathrm{R}(7,8) \quad$ 10. $(6,8) \mathrm{R}(7,5)$

$11$. $(7,8) \mathrm{R}(7,6) \quad$ 12. $(6,8) \mathrm{R}(6,4)$

$13$. $(6,6) \mathrm{R}(6,6)$

Total $24+1=25$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $a,\;b,\;c,\;d,\;e,\;f$ are in $A.P.$, then the value of $e - c$ will be
Let $X$ be a binomially distributed random variable with mean $4$ and variance $\frac{4}{3}$. Then $54 P ( X \leq 2)$ is equal to.
Solve system of linear equations, using matrix method. $2 x+y+z=1 ; x-2 y-z=\frac{3}{2} ; 3 y-5 z=9$
In the expansion of ${\left( {x - \frac{3}{{{x^2}}}} \right)^9},$ the term independent of $x$ is
If ${{3x + a} \over {{x^2} - 3x + 2}} = {A \over {(x - 2)}} - {{10} \over {x - 1}}$, then
The equation of circle which passes through the point $(1,1)$ and intersect the given circles ${x^2} + {y^2} + 2x + 4y + 6 = 0$ and ${x^2} + {y^2} + 4x + 6y + 2 = 0$ orthogonally, is
If $\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\ldots+\frac{1}{\sqrt{99}+\sqrt{100}}=m$ and $\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\ldots+\frac{1}{99 \cdot 100}=\mathrm{n}$, then the point $(\mathrm{m}, \mathrm{n})$ lies on the line
If ${x_n} = \frac{{1 - 2 + 3 - 4 + 5 - 6 + ..... - 2n}}{{\sqrt {{n^2} + 1} + \sqrt {4{n^2} - 1} }},$ then $\mathop {\lim }\limits_{n \to \infty } {x_n}$ is equal to
The number of $\theta \in(0,4 \pi)$ for which the system of linear equations

$3(\sin 3 \theta) x-y+z=2$, $3(\cos 2 \theta) x+4 y+3 z=3$, $6 x+7 y+7 z=9$ has no solution is.

Let $\omega = - \frac{1}{2} + i\frac{{\sqrt 3 }}{2}$. Then the value of the determinant $\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{ - 1 - {\omega ^2}}&{{\omega ^2}}\\1&{{\omega ^2}}&{{\omega ^4}}\end{array}\,} \right|$ is