Question
Let * be a binary operation defined on set Q − {1} by the rule a * b = a + b − ab. Then, the identify element for * is:
  1. $1$
  2. $\frac{\text{a}-1}{\text{a}}$
  3. $\frac{\text{a}}{\text{a}-1}$
  4. $0$

Answer

  1. $0$
Solution:
Let e be the identity element in Q - {1} with respect to * such that
a * e = a = e * a, $\forall\text{ a}\in\text{Q}-\{-1\}$
a * e = a and e * a = a, $\forall\text{ a}\in\text{Q}-\{-1\}$
a + e - ae = a and e + a - ea = a, $\forall\text{ a}\in\text{Q}-\{-1\}$
e(1 - a) = 0, $\forall\text{ a}\in\text{Q}-\{-1\}$ $[\because \text{a}\neq1]$
Thus, 0 is the identity element in Q - {1} with respect to *.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Choose the correct answer from the given four options.
Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is:
Choose the correct answer in each of the following:
If A and B are any two events such that P(A) + P(B) – P(A and B) = P(A), then
In a regular hexagon ABCDEF, $\overrightarrow{\text{AB}}=\vec{\text{a}},\ \overrightarrow{\text{BC}}=\vec{\text{b}}$ and $\overrightarrow{\text{CD}}=\vec{\text{c}}$. Then, $\overrightarrow{\text{AE}}=$
  1. $\vec{\text{a}}+\vec{\text{b}}+\vec{\text{c}}$
  2. $2\vec{\text{a}}+\vec{\text{b}}+\vec{\text{c}}$
  3. $\vec{\text{b}}+\vec{\text{c}}$
  4. $\vec{\text{a}}+2\vec{\text{b}}+2\vec{\text{c}}$
Which of the following is not correct?
  1. $|\text{A}|=|\text{A}^{\text{T}}|,$ where $\text{A}=[\text{a}_{\text{ij}}]_{3\times3}$
  2. $|\text{kA}|=|\text{k}^3|,$ where $\text{A}=[\text{a}_{\text{ij}}]_{3\times3}$
  3. If a is a skew-symmetric of odd order, then |A| = 0
  4. $\begin{vmatrix}\text{a}&\text{c}\\\text{e}&\text{g} \end{vmatrix}+\begin{vmatrix}\text{b}&\text{c}\\\text{f}&\text{g} \end{vmatrix}+\begin{vmatrix}\text{a}&\text{d}\\\text{e}&\text{h}\end{vmatrix}+\begin{vmatrix}\text{b}&\text{d}\\\text{f}&\text{h}\end{vmatrix}$
The vector component of $\vec{\text{b}}$ perpendicular to $\vec{\text{a}}$ is:
  1. $\big(\vec{\text{b}}.\vec{\text{c}}\big)\vec{\text{a}}$
  2. $\frac{\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)}{|\vec{\text{a}}|^2}$
  3. $\vec{\text{a}}\times\big(\vec{\text{b}}\times\vec{\text{a}}\big)$
  4. None of these
If $R =\left\{(x, y): x, y \in Z , x^2+y^2 \leq 4\right\}$ is a relation in Z then domain of R is :
A die is thrown once. Let $A$ be the event that the number obtained is greater than $3$ . Let $B$ be the event that the number obtained is less than $5$ . Then $P(A \cup B)$ is
Choose the correct answer in exercise:
$\int\frac{\text{dx}}{\text{x}(\text{x}^2+1)}$ equals
The solution of the differential equation $\frac{\text{dy}}{\text{dx}}=\frac{\text{y}}{\text{x}}+\frac{\phi(\frac{\text{y}}{\text{x}})}{\phi'(\frac{\text{y}}{\text{x}})}$ is:
  1. $\phi(\frac{\text{y}}{\text{x}})=\text{Kx}$
  2. $\text{x}\phi(\frac{\text{y}}{\text{x}})=\text{K}$
  3. $\phi(\frac{\text{y}}{\text{x}})=\text{Ky}$
  4. $\text{y}\phi(\frac{\text{y}}{\text{x}})=\text{K}$ 
Choose the correct answer from the given four options.
Family $\text{y}=\text{A}\text{x}+\text{A}^3$ of curves will correspond to a differential equation of order:
  1. 3
  2. 2
  3. 1
  4. Not defined